2085. Count Common Words With One Occurrence - LeetCode Solution

class Solution:
    def countWords(self, word1: List[str], word2: List[str]) -> int:
        dict = {}
        dict2 = {}
        for i in word1:
            if i in dict:
                dict[i] +=1
            else:
                dict[i] = 1
        for i in word2:
            if i in dict2:
                dict2[i] +=1
            else:
                dict2[i] = 1
        count = 0
        for i in dict:
            if dict[i] == 1:
                if i in dict2:
                    if dict2[i] == 1:
                        count+=1
        return count